解:對(duì)于方程$100(1 - x)^{2}=64,$兩邊同時(shí)除以$100,$得$(1 - x)^{2}=\frac{64}{100}。$直接開(kāi)平方,$1 - x=\pm\frac{8}{10}=\pm\frac{4}{5}。$當(dāng)$1 - x=\frac{4}{5}$時(shí),移項(xiàng)得$x=1-\frac{4}{5}=\frac{1}{5}。$當(dāng)$1 - x=-\frac{4}{5}$時(shí),移項(xiàng)得$x=1+\frac{4}{5}=\frac{9}{5}。$所以$x_{1}=\frac{1}{5},$$x_{2}=\frac{9}{5}。$