解:
(1)由表格可知,每增加1個碗,高度增加$2.4$cm,設$y = kx + b,$將$x = 1,$$y = 6;$$x = 2,$$y = 8.4$代入得:
$\begin{cases}k + b = 6\\2k + b = 8.4\end{cases}$
用$2k + b = 8.4$減去$k + b = 6$得:
$2k + b -(k + b)=8.4 - 6$
$2k + b - k - b = 2.4$
$k = 2.4$
把$k = 2.4$代入$k + b = 6$得:$2.4 + b = 6,$$b = 3.6。$
所以$y = 2.4x + 3.6。$
(2)根據(jù)題意,得$2.4x + 3.6\leqslant28.8$
$2.4x\leqslant28.8 - 3.6$
$2.4x\leqslant25.2$
$x\leqslant10.5$
所以碗的數(shù)量最多為10個。