解:由?$3\ \mathrm {m} - n = 2$?得?$n = 3\ \mathrm {m} - 2$?
?$ $?將?$n = 3\ \mathrm {m} - 2$?代入?$m + 2n = 11$?得:
?$ m + 2×(3\ \mathrm {m} - 2)=11,$?解得?$m = 3$?
?$ $?把?$m = 3$?代入?$n = 3\ \mathrm {m} - 2$?得?$n=7$?
∴方程組的解為?$\begin {cases}m = 3\\n = 1\end {cases}$?