$解：?(1)?把?x=0、??y=2、??h=2.6?代入?y=a(x-6)^2+h，?$
$即?2=a(0-6)^2+2.6?$
$∴?a=- \frac {1}{60}?$
$∴?y=- \frac {1}{60} (x-6)^2+2.6?$
$?(2) ?當(dāng)?h=2.6?時(shí)，?y=-\frac {1}{60} (x-6)^2+2.6，?$
$當(dāng)?x=9?時(shí)，?y=-\frac {1}{60} (9-6)^2+2.6=2.45\gt 2.43?$
∴球能越過(guò)網(wǎng)
$當(dāng)?x=18?時(shí)，?y=- \frac {1}{60} (18-6)^2+2.6=0.2\gt 0?$
∴球會(huì)出界
