$解：? (1)?相等，理由如下$
$由題意可知，?∠BPQ=90°-24.5°=65.5°，??∠PQB=90°-41°=49°?$
$∴?∠PBQ= 180°-∠BPQ-∠PQB=65.5°?$
$∴?∠BPQ=∠PBQ?$
$∴?BQ=PQ?$
$?(2)?由題意，?∠PQA=90°-49°=41°，??∠PQB=49°?$
$∴?∠AQB=∠AQP+∠PQB=90°?$
$?AQ=\frac {PQ}{cos 41°}≈1600m，??BQ=PQ=1200m?$
$∴?AB=\sqrt{AQ2+BQ2}= 2000m?$
$答：? A、??B?間的距離為?2000m。?$
