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電子課本網(wǎng) 第47頁(yè)

第47頁(yè)

信息發(fā)布者:
解:?$S_{正方形}={(a+5)}^2,$??$S_{長(zhǎng)方形}=a(a+6)$?
?$ S_{陰影}=S_{正方形}-S_{長(zhǎng)方形}$?
?$ ={(a+5)}^2-a(a+6)$?
?$ =a^2+10a+25-a^2-6a$?
?$ =4a+25$?
$ a$
$ 2x$
$ a^2-4x^2$
-1
$ \frac 13x$
$ 1-\frac 19x^2$
?$ =x^2-{(2y)}^2$?
?$ =x^2-4y^2$?
?$ =(\frac {1} {2}a)^2-(\frac {1} {3}b)^2$?
?$ =\frac {1} {4}a^2-\frac {1} {9}b^2$?
?$ =(5x^2)^2-(3y)^2$?
?$ ={25x}^4-9y^2$?
?$ =-(2a-3b)(2a+3b)$?
?$ =-[(2a)^2-(3b)^2]$?
?$ =-4a^2+9b^2$?
?$ =(100+3)×(100-3)$?
?$ ={100}^2-3^2$?
?$ =10000-9$?
?$ =9991$?
?$ ={1999}^2-(1999+1)×(1999-1)$?
?$ ={1999}^2-{1999}^2+1$?
?$ =1$?