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電子課本網(wǎng) 第106頁(yè)

第106頁(yè)

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解:∵?$|a|=2,$??$|b|=3$?
∴?$a=±2,$??$b=±3$?
∴當(dāng)?$a=2,$??$b=3$?時(shí),?$a+b=5;$?當(dāng)?$a=-2,$??$b=3$?時(shí),?$a+b=1;$?
當(dāng)?$a=2,$??$b=-3$?時(shí),?$a+b=-1;$?當(dāng)?$a=-2,$??$b=-3$?時(shí),?$a+b=-5 $?
解:當(dāng)?$m=1$?時(shí),函數(shù)是一個(gè)一次函數(shù)?$y=-x-1,$?它與?$x$?軸只有一個(gè)交點(diǎn)?$(-1,$??$0) $?
當(dāng)?$m≠1$?時(shí),函數(shù)是一個(gè)二次函數(shù)?$y=(m-1)x^2+(m-2)x-1$?
當(dāng)拋物線頂點(diǎn)恰巧在?$x$?軸上,函數(shù)圖像與?$x$?軸就只有一個(gè)公共點(diǎn)
由頂點(diǎn)縱坐標(biāo)?$ \frac {4ac-b^2}{4a}=\frac {-4(m-1)-(m-2)^2}{4(m-1)}=0$?
解得?$m=0$?
綜上所述,?$m=0$?或?$m=1 $?
解:當(dāng)所求點(diǎn)?$P $?為頂點(diǎn),即?$AB$?為底時(shí),作?$AB$?的垂直平分線,得格點(diǎn)?$P_{1}、$??$P_{2}、$??$P_{3};$?
當(dāng)點(diǎn)?$A$?為頂點(diǎn)時(shí),以點(diǎn)?$A$?為圓心,以?$AB$?為半徑作圓,得格點(diǎn)?$P_{4};$?
當(dāng)點(diǎn)?$B$?為頂點(diǎn)時(shí),以點(diǎn)?$B$?為圓心,以?$AB$?為半徑作圓,得格點(diǎn)?$P_{5}$?


解:如圖,作出函數(shù)?$y=x^2-2x-3=(x-1)^2-4$?的圖像
分以下情況討論:?$(1)x_{1}< x_{2}≤1,$??$y_{1}> y_{2}$?
?$(2)x_{1}< 1< x_{2},$?當(dāng)?$ \frac {x_{1}+x_{2}}{2} < 1$?時(shí),?$y_{1}> y_{2}$?
當(dāng)?$ \frac {x_{1}+x_{2}}{2}=1$?時(shí),?$y_{1}=y_{2};$?
當(dāng)?$ \frac {x_{1}+x_{2}}{2} > 1$?時(shí),?$y_{1}< y_{2}$?
?$(3)1≤x_{1}< x_{2},$??$y_{1}< y_{2}$?