解:如圖,作出函數(shù)?$y=x^2-2x-3=(x-1)^2-4$?的圖像
分以下情況討論:?$(1)x_{1}< x_{2}≤1,$??$y_{1}> y_{2}$?
?$(2)x_{1}< 1< x_{2},$?當(dāng)?$ \frac {x_{1}+x_{2}}{2} < 1$?時(shí),?$y_{1}> y_{2}$?
當(dāng)?$ \frac {x_{1}+x_{2}}{2}=1$?時(shí),?$y_{1}=y_{2};$?
當(dāng)?$ \frac {x_{1}+x_{2}}{2} > 1$?時(shí),?$y_{1}< y_{2}$?
?$(3)1≤x_{1}< x_{2},$??$y_{1}< y_{2}$?