解：?$(1)$?平移后的函數(shù)表達(dá)性為?$y=3(x-2)^2，$?對(duì)稱軸為直線?$x=2，$?頂點(diǎn)坐標(biāo)為?$(2，$??$0)$?
?$(2)$?平移后的函數(shù)表達(dá)性為?$y=3(x+\frac {2}{3})^2，$?對(duì)稱軸為直線?$x=-\frac {2}{3}，$?頂點(diǎn)坐標(biāo)為?$(-\frac {2}{3}，$??$0)$?
?$(3)$?平移后的函數(shù)表達(dá)性為?$y=3(x+1)^2+4，$?對(duì)稱軸為直線?$x=-1，$?頂點(diǎn)坐標(biāo)為?$(-1，$??$4)$?
