解：?$ (1)$?相等，理由如下
由題意可知，?$∠BPQ=90°-24.5°=65.5°，$??$∠PQB=90°-41°=49°$?
∴?$∠PBQ= 180°-∠BPQ-∠PQB=65.5°$?
∴?$∠BPQ=∠PBQ$?
∴?$BQ=PQ$?
?$(2)$?由題意，?$∠PQA=90°-49°=41°，$??$∠PQB=49°$?
∴?$∠AQB=∠AQP+∠PQB=90°$?
?$AQ=\frac {PQ}{cos 41°}≈1600m，$??$BQ=PQ=1200m$?
∴?$AB=\sqrt{AQ2+BQ2}= 2000m$?
答：?$ A、$??$B$?間的距離為?$2000m。$?
