?$解:如圖①,sinB=\frac {AD}{AB}=\frac {1}{2},∠B=30°$?
?$sinC=\frac {AD}{AC}=\frac {\sqrt{2}}{2},∠C= 45°$?
?$所以∠BAC=180°-30°-45°=105°$?
?$如圖②,cos∠DAC =\frac {AD}{AC}=\frac {\sqrt{2}}{2},∠DAC= 45°$?
?$cos∠DAB=\frac {AD}{AB}=\frac {1}{2},∠DAB=60°$?
?$所以∠BAC = 60°-45° = 15°$?