??$解:設(shè)零件邊長為x\ \mathrm {mm}$??
??$因為EF//AD//HG,$??
??$所以\frac {EF}{AD}=\frac {BF}{BD},\frac {HG}{AD}=\frac {CG}{CD}$??
??$即\frac {x}{80}=\frac {BF}{BD}=\frac {CG}{CD}=\frac {BF+CG}{BC}=\frac {120-x}{120}$??
??$解得x=48$??
??$正方形零件的邊長是48\ \mathrm {mm}$??