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電子課本網 第81頁

第81頁

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解:?$\frac {5x + 1}{6} = \frac {7}{2}$?
?$ $?兩邊乘以?$6$?得:?$5x + 1 = 21$?
移項得:?$5x = 20$?
?$ $?系數化為?$1$?得:?$x = 4$?
解:?$\frac {3 - x}{2} = \frac {x - 4}{3}$?
?$ $?兩邊乘以?$6$?得:?$3(3 - x) = 2(x - 4)$?
去括號得:?$9 - 3x = 2x - 8$?
移項得:?$-5x = -17$?
?$ $?系數化為?$1$?得:?$x = \frac {17}{5}$?
解:?$\frac {x}{2} - \frac {x - 1}{3} = 1$?
?$ $?兩邊乘以?$6$?得:?$3x - 2(x - 1) = 6$?
去括號得:?$3x - 2x + 2 = 6$?
移項得:?$x = 4$?
解:?$\frac {2x - 1}{0.7} + \frac {1}{7} = \frac {x}{0.3}$?
?$ $?兩邊分子分母同乘?$10$?化簡得:?$\frac {20x - 10}{7} + \frac {1}{7} = \frac {10x}{3}$?
?$ $?兩邊乘以?$21$?得:?$3(20x - 10) + 3 = 70x$?
去括號得:?$60x - 30 + 3 = 70x$?
移項得:?$-10x = 27$?
?$ $?系數化為?$1$?得:?$x = -2.7$?
解:根據題意,得?$\frac {x - 7}{5} - 1 = \frac {2x - 1}{2} + 3$?
去分母,兩邊同乘?$10,$?得?$2(x - 7) - 10 = 5(2x - 1) + 30$?
去括號,得?$2x - 14 - 10 = 10x - 5 + 30$?
移項,得?$2x - 10x = -5 + 30 + 14 + 10$?
合并同類項,得?$-8x = 49$?
?$ $?系數化為?$1,$?得?$x = -\frac {49}{8}$?
答:當?$x = -\frac {49}{8}$?時,兩個代數式的值相等。
解:?$(1)$?當?$a = 2,$??$b=\frac {7}{2},$??$h = 3$?時,
?$ S=\frac {1}{2}(a + b)h=\frac {1}{2}×(2+\frac {7}{2})×3=\frac {1}{2}×\frac {11}{2}×3=\frac {33}{4}$?
?$ (2)$?當?$a = 2,$??$h = 4,$??$S = 16$?時,
?$ 16=\frac {1}{2}(2 + b)×4$?
?$ 16=2(2 + b)$?
?$ 8=2 + b$?
?$ b=6$?
解:原方程可化為:$\frac{10(x + 4)}{2} - \frac{10(x - 3)}{5} = 2$
化簡得:$5(x + 4) - 2(x - 3) = 2$
去括號:$5x + 20 - 2x + 6 = 2$
移項:$5x - 2x = 2 - 20 - 6$
合并同類項:$3x = -24$
系數化為1:$x = -8$