解:?$(1)$?∵點?$A$?在?$y$?軸上,∴其橫坐標(biāo)為?$0,$?即?$3a - 5 = 0,$?解得?$a = \frac 53$?
此時點?$A$?的縱坐標(biāo)為?$a + 1 = \frac 53 + 1 = \frac 83,$?∴點?$A$?的坐標(biāo)為?$(0,$??$\frac 83)$?
?$ (2)$?∵點?$A$?到?$x$?軸的距離是?$2,$?∴點?$A$?縱坐標(biāo)的絕對值為?$2,$?即?$|a + 1| = 2$?
當(dāng)?$a + 1 = 2$?時,?$a = 1,$?此時點?$A$?的橫坐標(biāo)為?$3×1 - 5 = -2,$?坐標(biāo)為?$(-2,$??$2)$?
當(dāng)?$a + 1 = -2$?時,?$a = -3,$?此時點?$A$?的橫坐標(biāo)為?$3×(-3) - 5 = -14,$?坐標(biāo)為?$(-14,$??$-2)$?
綜上,點?$A$?的坐標(biāo)為?$(-2,$??$2)$?或?$(-14,$??$-2)$?