解:?$(1)$?∵點?$P $?在?$x$?軸上,∴其縱坐標為?$0,$?即?$m-1=0,$?解得?$m=1$?
則橫坐標為?$2\ \mathrm {m}+4=2×1+4=6,$?∴點?$P $?的坐標為?$(6,$??$0)$?
?$(2)$?∵點?$P $?縱坐標比橫坐標大?$3,$?∴?$(m-1)-(2\ \mathrm {m}+4)=3$?
即?$m-1-2\ \mathrm {m}-4=3,$?解得?$m=-8$?
橫坐標為?$2×(-8)+4=-12,$?縱坐標為?$-8-1=-9$?
∴點?$P $?的坐標為?$(-12,$??$-9)$?