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信息發(fā)布者：
解：?$ x^2-\frac 32x+\frac 9{16}=\frac 9{16}$?
?$ (x-\frac 34)^2=\frac 9{16}$?
?$ x-\frac 34=±\frac 34$?
?$ x_{1}=0，$??$x_{2}=\frac 32$?
解：?$ x^2+\frac 32x+\frac 12=0$?
?$ x^2+\frac 32x+\frac 9{16}=\frac 1{16}$?
?$ (x+\frac 34)^2=\frac 1{16}$?
?$ x+\frac 34=±\frac 14$?
?$ x_{1}=-\frac 12，$??$x_{2}=-1$?
解：?$ x^2-\frac 13x+\frac 1{36}=\frac {25}{36}$?
?$ (x-\frac 16)^2=\frac {25}{36}$?
?$ x-\frac 16=±\frac 56$?
?$ x_{1}=1，$??$x_{2}=-\frac 23$?
解：?$ x^2-\frac 12x+\frac 1{16}=\frac 5{16}$?
?$ (x-\frac 14)^2=\frac 5{16}$?
?$ x-\frac 14=±\frac {\sqrt 5}4$?
?$ x_{1}=\frac {1+\sqrt 5}4，$??$x_{2}=\frac {1-\sqrt 5}4$?
解：?$ x^2-\frac 32x+\frac 9{16}=\frac {33}{16}$?
?$ (x-\frac 34)^2=\frac {33}{16}$?
?$ x-\frac 34=±\frac {\sqrt {33}}4$?
?$ x_{1}=\frac {3+\sqrt {33}}4，$??$x_{2}=\frac {3-\sqrt {33}}4$?
解：?$ x^2-\frac 14x+\frac 1{64}= \frac {17}{64}$?
?$ (x-\frac 18)^2=\frac {17}{64}$?
?$ x-\frac 18=±\frac {\sqrt {17}}8$?
?$ x_{1}=\frac {1+\sqrt {17}}8，$??$x_{2}=\frac {1- \sqrt {17}}8$?
解：?$ y^2+\frac 52y+\frac {25}{16}=\frac {17}{16}$?
?$ (y+\frac 54)^2=\frac {17}{16}$?
?$ y+\frac 54=±\frac {\sqrt {17}}4$?
?$ y_{1}=\frac {-5+\sqrt {17}}4，$??$y_{2}=\frac {-5-\sqrt {17}}4$?
解：?$ x^2-3x+\frac 94=\frac 7{12}$?
?$ (x-\frac 32)^2=\frac 7{12}$?
?$ x-\frac 32=±\frac {\sqrt {21}}6$?
?$ x_{1}=\frac {9+\sqrt {21}}6，$??$x_{2}=\frac {9-\sqrt {21}}6$?
解：?$ x^2-14x+24=0$?
?$ x^2-14x+49=25$?
?$ (x-7)^2=25$?
?$ x-7=±5$?
?$x_{1}=12($?舍去?$)，$??$x_{2}=2$?
答：小路的寬為?$2\ \mathrm {m}。$?
解：?$ x^2+2x+\frac 72=0$?
?$ x^2+2x+1=-\frac 52$?
?$ (x+1)^2=-\frac 52$?
∵不存在實數(shù)根的平方為負數(shù)
∴該方程沒有實數(shù)根
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