亚洲激情+欧美激情,无码任你躁久久久久久,我的极品美女老婆,性欧美牲交在线视频,亚洲av高清在线一区二区三区

第8頁

信息發(fā)布者：
解：??$x(x - 4)=0$??
??$x = 0$??或??$x - 4 = 0$??
??$x_{1} = 0，$????$x_{2} = 4$??
解：??$(2y + 1)(y - 2)=0$??
??$2y + 1 = 0$??或??$y - 2 = 0$??
??$y_{1} = -\frac {1}{2}，$????$y_{2} = 2$??
解：??$2(x - 4)+x(x - 4)=0$??
??$(x - 4)(2 + x)=0$??
??$ x - 4 = 0$??或??$2 + x = 0$??
??$x_{1} = 4，$????$x_{2} = - 2$??
解：??$4x(5x - 2)=3(5x - 2)$??
??$(5x - 2)(4x - 3)=0$??
??$5x - 2 = 0$??或??$4x - 3 = 0$??
??$x_{1}=\frac {2}{5}，$????$x_{2}=\frac {3}{4}$??
解：由?$x^2 - 49 = 0$?得?$x^2=49，$?
所以?$x=\pm\sqrt{49}=\pm7，$
?即?$x_1 = 7，$??$x_2 = - 7。$?
解：由?$(x + 1)^2 - 25 = 0$?得?$(x + 1)^2=25，$?
則?$x + 1=\pm\sqrt{25}=\pm5。$?
當(dāng)?$x + 1 = 5$?時(shí)，解得?$x_1 = 4；$?
當(dāng)?$x + 1 = - 5$?時(shí)，解得?$x_2 = - 6。$?
解：??$\frac {1}{2}(x - 2)^2 - 8 = 0$??
??$(x - 2)^2 = 16$??
??$ x - 2=\pm \sqrt {16}=\pm 4$??
??$ $??當(dāng)??$x - 2 = 4$??時(shí)，解得??$x_{1} = 6$??
??$ $??當(dāng)??$x - 2 = - 4$??時(shí)，解得??$x_{2} = - 2$??
解：??$(2x - 1)^2 - x^2 = 0$??
??$(2x - 1 + x)(2x - 1 - x)=0$??
??$(3x - 1)(x - 1)=0$??
??$x_{1}=\frac {1}{3}，$????$x_{2} = 1$??
上一頁 下一頁