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電子課本網(wǎng) 第83頁

第83頁

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解:?$②×2+①,$?得
?$0.3x-0.6y + 0.2x + 0.6y = 1 + 1.5$?
解得?$x = 5,$?
?$ $?把?$x = 5$?代入?$①,$?得?$0.2×5+0.6y = 1.5$?
解得?$y=\frac {5}{6},$?
?$ $?所以原方程組的解為?$\begin {cases}x = 5\\y =\dfrac {5}{6}\end {cases}$?
解:?$①×4,$?得?$2(x - 3)-12(y - 1)=0 ③$?
③ - ②,得?$-10(y - 1)=0,$?解得?$y = 1,$?
?$ $?把?$y = 1$?代入?$②,$?得?$2(x - 3)=0,$?解得?$x = 3,$?
?$ $?所以原方程組的解是?$\begin {cases}x = 3\\y = 1\end {cases}$?
解:原方程組可化為
?$\begin {cases}5(x - y)-4(x + y)=-2&①\\2(x - y)+3(x + y)=36&②\end {cases}$?
?$ ①×3+②×4,$?得?$23(x - y)=138,$?
解得?$x - y = 6,$?
?$ $?把?$x - y = 6$?代入?$①,$?得?$x + y = 8,$?
?$ $?則方程組轉(zhuǎn)化為?$\begin {cases}x - y = 6&③\\x + y = 8&④\end {cases}$?
③ + ④,得?$2x = 14,$?解得?$x = 7,$?
?$ $?把?$x = 7$?代入?$④,$?得?$7 + y = 8,$?解得?$y = 1,$?
?$ $?所以原方程組的解為?$\begin {cases}x = 7\\y = 1\end {cases}$?
解:因為甲得到的算式為?$(2x - a)(3x + b)$?
?$=6x^2+(2b - 3a)x - ab = 6x^2+11x - 10,$?
?$ $?所以?$2b - 3a = 11,$??$ab = 10,$?
?$ $?乙得到的算式為?$(2x + a)(x + b)=2x^2+(2b + a)x $?
?$+ ab = 2x^2-9x + 10,$?
?$ $?所以?$2b + a = -9,$??$ab = 10,$?
?$ $?則?$\begin {cases}2b - 3a = 11&①\\2b + a = -9&②\end {cases}$?
① - ②,得?$-4a = 20,$?解得?$a = -5,$?
?$ $?將?$a = -5$?代入?$①,$?得?$2b-3×(-5)=11,$?
解得?$b = -2,$?
?$ $?所以正確的式子為?
$(2x - 5)(3x - 2)=6x^2-19x + 10。$?
$\begin{cases}x=\frac{1}{2}\\y = -\frac{7}{2}\end{cases}$
解:?$(1)① - ②,$?得?$2x + 2y = 2,$?
即?$x + y = 1 ③,$?
?$ ③×2023,$?得?$2023x + 2023y = 2023 ④,$?
④ - ②,得?$y = 2,$?
?$ $?將?$y = 2$?代入?$③,$?得?$x + 2 = 1,$?
解得?$x = -1,$?
?$ $?所以原方程組的解是?$\begin {cases}x = -1\\y = 2\end {cases};$?
?$ (2)① - ②,$?得?$(a - b)x+(a - b)y=a - b,$
?即?$x + y = 1 ③,$?
?$ ③×(a + 2),$?得?$(a + 2)x+(a + 2)y=a + 2 ④,$?
④ - ①,得?$y = 2,$?
?$ $?將?$y = 2$?代入?$③,$?得?$x + 2 = 1,$?解得?$x = -1,$?
?$ $?所以原方程組的解為?$\begin {cases}x = -1\\y = 2\end {cases}$?