解:因為甲得到的算式為?$(2x - a)(3x + b)$?
?$=6x^2+(2b - 3a)x - ab = 6x^2+11x - 10,$?
?$ $?所以?$2b - 3a = 11,$??$ab = 10,$?
?$ $?乙得到的算式為?$(2x + a)(x + b)=2x^2+(2b + a)x $?
?$+ ab = 2x^2-9x + 10,$?
?$ $?所以?$2b + a = -9,$??$ab = 10,$?
?$ $?則?$\begin {cases}2b - 3a = 11&①\\2b + a = -9&②\end {cases}$?
① - ②,得?$-4a = 20,$?解得?$a = -5,$?
?$ $?將?$a = -5$?代入?$①,$?得?$2b-3×(-5)=11,$?
解得?$b = -2,$?
?$ $?所以正確的式子為?
$(2x - 5)(3x - 2)=6x^2-19x + 10。$?