解:
?$ \begin {aligned}&(-x - 2y)(2y - x)-(2x - y)^2+(3x - y)(2x - 5y)\\=&x^2-4y^2-(4x^2-4xy + y^2)+(6x^2-15xy-2xy + 5y^2)\\=&x^2-4y^2-4x^2+4xy - y^2+6x^2-17xy + 5y^2\\=&3x^2-13xy\end {aligned}$?
?$ $?當?$x=-1,$??$y = - 2$?時,
原式?$=3×(-1)^2-13×(-1)×(-2)=3 - 26=-23。$?