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第4頁

信息發(fā)布者:
C
C
D
$x\geqslant -\frac{1}{2}$
$\pm5$
$\sqrt{3}$
$-\frac{2}{3}$
$\sqrt{2}$(答案不唯一)
$ \begin{aligned}解:&(\pi - 3)^0 - 2\sin60^{\circ}+\vert-\sqrt{3}\vert \\ =&1 - 2\times\frac{\sqrt{3}}{2}+\sqrt{3} \\ =&1-\sqrt{3}+\sqrt{3} \\ =&1 \\ \end{aligned}$
$ \begin{aligned}解:&(-1)^{2022}+\vert\sqrt{3}-3\vert - (\frac{1}{3})^{-1}+\sqrt{9} \\ =&1 + 3-\sqrt{3}-3 + 3 \\ =&4-\sqrt{3} \\ \end{aligned}$
$ \begin{aligned}解:&\frac{1}{2}\times(\sqrt{3}-1)^2+\frac{1}{\sqrt{2}}+\sqrt{3} \\ =&\frac{1}{2}\times(3 - 2\sqrt{3}+1)+\frac{\sqrt{2}}{2}+\sqrt{3} \\ =&\frac{1}{2}\times(4 - 2\sqrt{3})+\frac{\sqrt{2}}{2}+\sqrt{3} \\ =&2-\sqrt{3}+\frac{\sqrt{2}}{2}+\sqrt{3} \\ =&2+\frac{\sqrt{2}}{2} \\ \end{aligned}$