$解：?(1)?將? △A_1B_1C_1?向右平移?3?格，再向上平移?4?格$
$然后繞點(diǎn)? C_1?順時(shí)針旋轉(zhuǎn)?90°，?即可與 重合$
$?(2) ?將? \triangle A_1\ \mathrm {B}_1\ \mathrm {C}_1 ?繞點(diǎn)? A_1 ?按逆時(shí)針方向旋轉(zhuǎn)? 90° ?$
$ 即可得到與? \triangle A_2\ \mathrm {B}_2\ \mathrm {C}_2 ?成中心對(duì)稱圖形，對(duì)稱中心?P?$
如圖所示
