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電子課本網(wǎng) 第82頁

第82頁

信息發(fā)布者:
10bc
x
$??\frac {2y}{x-2}??$
$??b^2??$
$??x≠1??$
C
A
$解:原式??=\frac {-a3b}{2c}×\frac {-6cd}{5ab2}??$
$?? =\frac {3a2d}{5b}??$
$解:原式?=\frac {y-3}{4(y-2)}÷\frac {y2-4-5}{y-2}?$
$? =\frac {y-3}{4(y-2)}×\frac {y-2}{(y+3)(y-3)}?$
$? =\frac {1}{4(y+3)}?$
$? =\frac {1}{4y+12}?$