$??解:設AE=x,則AB^2=2^2+x^2,AD^2=6^2+x^2?$
$?在Rt△ABD中,∵ AD^2+AB^2=BD^2?$
$?∴ 36+{x}^{2}+4+{x}^{2}={8}^{2}?$
$?解得,x=±2{\sqrt {3}}?$
$?∵ x>0?$
$?∴ x=2{\sqrt {3}}?$
$?∴ AB={\sqrt {{2}^{2}+{x}^{2}}}=4,AD={\sqrt {{6}^{2}+{x}^{2}}}=4{\sqrt {3}}?$
$?∴ 矩形ABCD的長為4\sqrt {3},寬為4?$