亚洲激情+欧美激情,无码任你躁久久久久久,我的极品美女老婆,性欧美牲交在线视频,亚洲av高清在线一区二区三区
首 頁
電子課本網(wǎng)
›
第76頁
第76頁
信息發(fā)布者:
$解:因?yàn)?\frac {1}{x}-\frac {1}{y}=3?$
$? \frac {1}{x}-\frac {1}{y}=\frac {y-x}{xy}=3?$
$ 所以?y-x=3xy?$
$ 原式?=\frac {x-(y-x)-y}{2x+y-x-2y}?$
$? =\frac {2(x-y)}{x-y}?$
$? =2?$
D
A
$解:原式?=\frac {a-b}{a-b}×\frac {ab}{a-b}?$
$? =\frac {ab}{a-b}?$
$解:原式?=\frac {x(x+2)-x(x-2)}{(x-2)(x+2)}×\frac {2-x}{4x}?$
$? =\frac {4x}{(x+2)(x-2)}×\frac {2-x}{4x}?$
$? =-\frac {1}{x+2}?$
$解:原式?=1-\frac {a-b}{a+2b}×\frac {(a+2b)2}{(a-b)(a+b)}?$
$? =1-\frac {a+2b}{a+b}?$
$? =-\frac {a+b}$
$解:原式?=\frac {a2-b2+2b2}{a-b}?$
$? =\frac {a2+b2}{a-b}?$
$解:原式?=\frac {(x-y)2+4xy}{x-y}×\frac {(x+y)2-4xy}{x+y}?$
$?=\frac {(x+y)2}{x-y}×\frac {(x-y)2}{x+y}?$
$?=(x+y)(x-y)?$
$? =x2-y2$
$解:原式?=\frac {m+2-(m-2)}{(m+2)(m-2)}??+\frac {2(m-1)-2(m+1)}{(m+1)(m-1)}?$
$? =\frac {4}{(m+2)(m-2)}-\frac {4}{(m+1)(m-1)}?$
$? =\frac {12}{(m+2)(m-2)(m+1)(m-1)}?$
上一頁
下一頁
電子課本網(wǎng)手機(jī)版
免責(zé)申明:本站所有文章,圖片來源于網(wǎng)絡(luò),著作權(quán)及版權(quán)歸原作者所有