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第67頁

信息發(fā)布者：

$?=(\frac {\sqrt 3}2)^2+(\frac 12)^2?$

$?=\frac 34+\frac 14?$

$?=1?$

$?=\frac {(\frac {\sqrt 2}2)^2+\sqrt 3}1?$

$?=\frac 12+\sqrt 3?$

$?=\frac {2×\frac {\sqrt 3}2-1}{\frac 12-2×1}?$

$?=\frac {\sqrt 3-1}{\frac 12-2}?$

$?=\frac {2-2\sqrt 3}3?$

$?=\frac {1-\frac 12}{\frac {\sqrt 3}2}×\frac {\sqrt 3}3?$

$?=\frac {1}{\sqrt 3}×\frac {\sqrt 3}3?$

$?=\frac 13?$

8

$?\frac {\sqrt 5}5 ?$

C

D

$=\sqrt 3×\frac 12+3×\frac {\sqrt 3}2-4×1?$

$?=\frac {\sqrt 3}2+\frac {3\sqrt 3}2-4?$

$?=2\sqrt 3-4$

$?=\frac {\sqrt 3}3×\frac {\sqrt 2}2+\sqrt 3×\frac {\sqrt 2}2?$

$?=\frac {\sqrt 6}6+\frac {\sqrt 6}2?$

$?=\frac {2\sqrt 6}3?$

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