$解:(1)點(diǎn)B是點(diǎn)D,F關(guān)于直線AB的“等角點(diǎn)”,理由如下:\ $
$∵點(diǎn)D,E關(guān)于直線AB對(duì)稱,∴BE=BD,AB⊥DE$
$∴∠ABE=∠ABC$
$∵∠ABE=∠MBF,∴∠ABC=∠MBF$
$∴點(diǎn)B是點(diǎn)D,F關(guān)于直線AB的“等角點(diǎn)”$
$(2)解:∵∠A=70°,AB=AC,∴∠ABC=∠ACB=55°$
$∵點(diǎn)D,Q關(guān)于直線AB,AC的“等角點(diǎn)”分別為點(diǎn)B和點(diǎn)C$
$∴∠MBQ=∠NCQ=55°$
$∴∠CBQ=∠BCQ=70°,∴∠BQC=40°$
