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電子課本網(wǎng) 第57頁(yè)

第57頁(yè)

信息發(fā)布者:
(-a,b)

$解:(1)C_{1}(-2,1)$
$(2)S_{△ABC}=5×5-\frac{1}{2}×4×5-\frac{1}{2}×1×3-\frac{1}{2}×5×2= 8.5$
$(3)P(6,4)或(-2,-4)$

(更多請(qǐng)點(diǎn)擊查看作業(yè)精靈詳解)
$解:A_{1}(0,4),B_{1}(2, 2),C_{1}(1,1)$
$解:如答圖②,當(dāng)0\lt a≤3時(shí)$
$∵點(diǎn)P與點(diǎn)P_{1}關(guān)于y軸對(duì)稱(chēng),P(-a,0),∴P_{1}(a,0)$
$設(shè)P_{2}(x_{1},0),又∵點(diǎn)P_{1}與點(diǎn)P_{2}關(guān)于直線l對(duì)稱(chēng)$
$∴\frac{x_{1}+a}{2}=3,即x_{1}=6-a$
$∴P_{2}(6-a,0),則P_{1}P_{2}=6-a-a=6-2a$

$如答圖③當(dāng)a>3時(shí)$
$∵點(diǎn)P與點(diǎn)P_{1}關(guān)于y軸對(duì)稱(chēng),P(-a,0),∴P_{1}(a,0)$
$設(shè)P_{2}(x_{2},0),又∵點(diǎn)P_{1}與點(diǎn)P_{2}關(guān)于直線l對(duì)稱(chēng)$
$∴\frac {x_{2}+a}{2}=3,即x_{2}=6-a$
$∴P_{2}(6-a,0)$
$則P_{1}P_{2}=a-(6-a)=2a-6$
$綜上所述,當(dāng)0\lt a≤3時(shí),P_{1}P_{2}=6-2a$
$當(dāng)a>3時(shí),P_{1}P_{2}=2a-6$

$解:當(dāng)0\lt a≤3時(shí),PP_{2}=PP_{1}+P_{1}P_{2}$
$=2a+6-2a=6$
$當(dāng)a>3時(shí),PP_{2}=PP_{1}-P_{1}P_{2}=2a-(2a-6)=6$
$∴PP_{2}的長(zhǎng)不會(huì)隨著點(diǎn)P位置的變化而變化$