解:?$(1)$?∵?$AB=20$?,?$BC=15$?
∴?$AC=AB-BC=20-15=5$?
又∵?$M$?是線段?$AC$?的中點(diǎn)
∴?$AM=\frac {1}{2}AC=\frac {1}{2}×5=\frac {5}{2}$?,即線段?$AM$?的長(zhǎng)是?$\frac {5}{2}$?
?$(2)$?∵?$BC=15$?,?$CN∶NB=2∶3$?
∴?$CN=\frac {2}{5}BC=\frac {2}{5}×15=6.$?
又∵?$MC=AM=\frac {5}{2}$?
∴?$MN=MC+CN=\frac {17}{2}$?,即線段?$MN$?的長(zhǎng)是?$\frac {17}{2}$?