解:?$(1)$?將?$A(1,$??$6)$?代入?$y=\frac mx,$?得
?$m=6$?
設(shè)直線?$AB$?的函數(shù)表達(dá)式為?$y=kx+b,$?
將?$A(1,$??$6)$?和?$B(6,$??$1)$?代入?$y=kx+b,$?得?${{\begin{cases} {{k+b=6}} \\{6k+b=1} \end{cases}}}$?
解得,?${{\begin{cases} {{k=-1}} \\{b=7} \end{cases}}}$?
∴直線?$AB$?的函數(shù)表達(dá)式為?$y=-x+7$?
?$(2)(2,$??$4),$??$(3,$??$3),$??$(4,$??$2)$?