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第8頁

信息發(fā)布者:
解?$:(1)$?原式?$=\frac {1}{3}+0.3-\frac {1}{3} $?
?$=0.3 ; $?
?$(2)$?原式?$=\sqrt {6}-\frac {1}{2} \sqrt {2}-2 \sqrt {6}-\frac {2}{3} \sqrt {6} $?
?$=-\frac {5}{3} \sqrt {6}-\frac {1}{2} \sqrt {2} ;$?
?$(3)$?原式?$= {[\sqrt {3}+\sqrt {5}+\sqrt {6}-(\sqrt {3}-\sqrt {5}+\sqrt {6})]·} $?
?$ {[\sqrt {3}+\sqrt {5}+\sqrt {6}+(\sqrt {3}-\sqrt {5}+\sqrt {6})] } $?
?$= 4 \sqrt {5}(\sqrt {3}+\sqrt {6}) $?
?$= 4 \sqrt {15}+4 \sqrt {30}$?

解:∵?$x=\frac {1}{2}(3+\sqrt {3}), y=\frac {1}{2}(3-\sqrt {3}), $?
∴?$x+y=3, x y=\frac {1}{4}(9-3)=\frac {3}{2}, $?
∴?$x^2+x y+y^2=(x+y)^2-x y=9 -\frac {3}{2}=\frac {15}{2}$?