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電子課本網(wǎng) 第74頁

第74頁

信息發(fā)布者:
B
A
C
x≠-1
x=1
-3
$ \frac {x+4}{2x^2}$
$ \frac 1{a+1}$
1
$ a<-1$
4
解:原式?$= -\frac {x^2}{x-2}+\frac 4{x-2}$?
?$ =-\frac {(x+2)(x-2)}{x-2}$?
?$ =-x-2$?
解:原式?$= (a-1)×\frac {a+2}{(a+1)(a-1)}+\frac {a+3}{a+2}×\frac {a+2}{(a+1)(a-1)}$?
?$ =\frac {a+2}{a+1}+\frac {a+3}{a^2-1}$?
?$ =\frac {(a+2)(a-1)+a+3}{a^2-1}$?
?$ =\frac {a+1}{a-1}$?