解:?$ (1)$?構(gòu)建一個(gè)直角三角形?$ABC$?
當(dāng)?$AB=3,$??$AC=4$?
∴?$cos-A =\sqrt{AC2-AB2}=\sqrt{7}$?
?$tan α= tan A=\frac {BC}{AB}=\frac {\sqrt{7}}{3}$?
∵?$\sqrt{7}< 3$?
∴?$\frac {\sqrt{7}}{3}<1<\frac {5}{4}$?
∴?$tan α< tan β$?
∴α<β
?$(2)$?構(gòu)建直角三角形?$ABC。$?
當(dāng)?$BC=4,$??$AC= 10$?時(shí)
?$sinA=\frac {BC}{AC}= 0.4$?
?$AB=\sqrt{AC2-BC2}= 2\sqrt{21}$?
?$cos α= cos-A= \frac {AB}{BC}=\frac {\sqrt{21}}{5}≈0.92$?
∴?$cosa>cosβ$?
∴?$a<β$?