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第7頁

信息發(fā)布者:

9
4
1
0
1
4
9
-9
-4
-1
0
-1
-4
-9
?$\frac {9}{2}$?
0
?$\frac {1}{2}$?
0
?$\frac {1}{2}$?
2
?$\frac {9}{2}$?
?$-\frac {9}{2}$?
-2
?$-\frac {1}{2}$?
0
?$-\frac {1}{2}$?
2
?$-\frac {9}{2}$?
解:共同點:?$4$?個函數(shù)圖像的頂點都在原點,對稱軸都是?$y$?軸.
不同點:二次函數(shù)?$y=x2,$??$y=\frac {1}{2}x2$?的圖像開口向上,頂點是拋物線的最低點;
二次函數(shù)?$y=-x2、$??$y=-\frac {1}{2}x2$?的圖像開口向下,頂點是拋物線的最高點
解:當(dāng)?$a>0$?時,拋物線開口方向向上,頂點坐標(biāo)為?$(0,$??$0),$?關(guān)于?$y$?軸對稱,
函數(shù)在?$x<0$?時,?$y$?隨?$x$?的增大而減小,當(dāng)?$x> 0$?時,?$y$?隨?$x$?的增大而增大,
函數(shù)在?$x=0$?時,取最小值?$y=0。$?
當(dāng)?$a<0$?時,拋物線開口方向向下,頂點坐標(biāo)為?$(0,$??$0),$?關(guān)于?$y$?軸對稱,
函數(shù)在?$x<0$?時,?$y$?隨?$x$?的增大而增大,當(dāng)?$x> 0$?時,?$y$?隨?$x$?的增大而減小,
函數(shù)在?$x=0$?時,取最大值?$y=0。$?