亚洲激情+欧美激情,无码任你躁久久久久久,我的极品美女老婆,性欧美牲交在线视频,亚洲av高清在线一区二区三区

電子課本網(wǎng) 第106頁

第106頁

信息發(fā)布者:
解:$x + 45\%x = 14.5$
$1.45x = 14.5$
$x = 14.5\div1.45$
$x = 10$
解:$1 + 45\%x = 14.5$
$0.45x = 14.5 - 1$
$0.45x = 13.5$
$x = 13.5\div0.45$
$x = 30$
解:$2x - 96\%x = 0.26$
$2x - 0.96x = 0.26$
$1.04x = 0.26$
$x = 0.26\div1.04$
$x = 0.25$
解:$3x + 90\%\times4 = 9$
$3x + 0.9\times4 = 9$
$3x + 3.6 = 9$
$3x = 9 - 3.6$
$3x = 5.4$
$x = 5.4\div3$
$x = 1.8$
$=7×\frac{9}{7}+\frac{7}{9}×\frac{1}{7} =9+\frac{1}{9} =9\frac{1}{9}$
$=24÷0.4÷\frac{5}{8} =60×\frac{8}{5} =96 $
$=\frac{2}{7}×\frac{1}{5}+\frac{5}{7}×\frac{1}{5}$
$=(\frac{2}{7}+\frac{5}{7})×\frac{1}{5}$
$=1×\frac{1}{5}$
$=\frac{1}{5}$
$=\frac{8}{9}÷[(\frac{3}{6}+\frac{1}{6})×\frac{4}{3}] =\frac{8}{9}÷[\frac{4}{6}×\frac{4}{3}] =\frac{8}{9}÷[\frac{2}{3}×\frac{4}{3}] =\frac{8}{9}÷\frac{8}{9} =1 $
$=\frac{8}{17}×\frac{1}{23}+\frac{1}{23}×\frac{9}{17} $
$=1×\frac{1}{23}$
$=\frac{1}{23}$
$=\frac{3}{4}÷[56×\frac{3}{7}-56×\frac{3}{8}]$
$=\frac{3}{4}÷[24 - 21]$
$=\frac{3}{4}÷3$
$=\frac{3}{4}×\frac{1}{3}$
$=\frac{1}{4}$
$=\frac{5}{8}×8+\frac{1}{27}×8+\frac{19}{27} =5+\frac{8}{27}+\frac{19}{27} =5 + 1 =6 $
$=35×\frac{8}{7}-\frac{2}{7}$
$=40 - \frac{2}{7}$
$=39\frac{5}{7}$
【答案】:
       解:1.45x=14.5
                      x=14.5÷1.45
                      x=10
   解:0.45x=14.5-1
                  x=13.5÷0.45
                  x=30
         解:1.04x=0.26
                        x=0.26÷1.04
                        x=0.25
                解:3x=9-3.6
                         x=5.4÷3
                          x=1.8

【解析】:
解:$x + 45\%x = 14.5$
$1.45x = 14.5$
$x = 10$
解:$1 + 45\%x = 14.5$
$0.45x = 13.5$
$x = 30$
解:$2x - 96\%x = 0.26$
$1.04x = 0.26$
$x = 0.25$
解:$3x + 90\%×4 = 9$
$3x + 3.6 = 9$
$3x = 5.4$
$x = 1.8$
【答案】:
$? =7×\frac 97+\frac 79×\frac 17?$
$? =9+\frac 19?$
$? =9\frac 19?$
$? =24÷0.4×\frac 85?$
$? =60×\frac 85?$
? =96?
$? =\frac 27×\frac 15+\frac 57×\frac 15?$
$? =(\frac 27+\frac 57)×\frac 15?$
$? =\frac 15?$
$? =\frac 89÷[\frac 23×\frac 43]?$
$? =\frac 89÷\frac 89?$
? =1?
$? =\frac 8{17}×\frac 1{23}+\frac 1{23}×\frac 9{17}?$
$? =(\frac 8{17}+\frac 9{17})×\frac 1{23}?$
$? =\frac 1{23}?$
$? =\frac 34÷[56×\frac 37-56×\frac 38]?$
$? =\frac 34÷[24-21]?$
$? =\frac 34÷3?$
$? =\frac 14?$
$? =\frac 58×8+8×\frac 1{27}+\frac {19}{27}?$
$? =5+\frac 8{27}+\frac {19}{27}?$
? =6?
$? =35×\frac 87×1-\frac 27?$
$? =40-\frac 27?$
$? =39\frac 57?$

【解析】:
$7÷\frac{7}{9}+\frac{7}{9}÷7$
$=7×\frac{9}{7}+\frac{7}{9}×\frac{1}{7}$
$=9+\frac{1}{9}$
$=9\frac{1}{9}$
$24÷(1 - 60\%)÷\frac{5}{8}$
$=24÷0.4÷\frac{5}{8}$
$=60×\frac{8}{5}$
$=96$
$\frac{2}{7}×20\%+\frac{5}{7}×\frac{1}{5}$
$=\frac{2}{7}×\frac{1}{5}+\frac{5}{7}×\frac{1}{5}$
$=(\frac{2}{7}+\frac{5}{7})×\frac{1}{5}$
$=1×\frac{1}{5}$
$=\frac{1}{5}$
$\frac{8}{9}÷[(\frac{1}{2}+\frac{1}{6})÷\frac{3}{4}]$
$=\frac{8}{9}÷[(\frac{3}{6}+\frac{1}{6})×\frac{4}{3}]$
$=\frac{8}{9}÷[\frac{4}{6}×\frac{4}{3}]$
$=\frac{8}{9}÷[\frac{2}{3}×\frac{4}{3}]$
$=\frac{8}{9}÷\frac{8}{9}$
$=1$
$\frac{8}{17}÷23+\frac{1}{23}×\frac{9}{17}$
$=\frac{8}{17}×\frac{1}{23}+\frac{1}{23}×\frac{9}{17}$
$=(\frac{8}{17}+\frac{9}{17})×\frac{1}{23}$
$=1×\frac{1}{23}$
$=\frac{1}{23}$
$\frac{3}{4}÷[56×(\frac{3}{7}-\frac{3}{8})]$
$=\frac{3}{4}÷[56×\frac{3}{7}-56×\frac{3}{8}]$
$=\frac{3}{4}÷[24 - 21]$
$=\frac{3}{4}÷3$
$=\frac{3}{4}×\frac{1}{3}$
$=\frac{1}{4}$
$(\frac{5}{8}+\frac{1}{27})×8+\frac{19}{27}$
$=\frac{5}{8}×8+\frac{1}{27}×8+\frac{19}{27}$
$=5+\frac{8}{27}+\frac{19}{27}$
$=5 + 1$
$=6$
$35÷\frac{7}{8}×1-\frac{2}{7}$
$=35×\frac{8}{7}-\frac{2}{7}$
$=40 - \frac{2}{7}$
$=39\frac{5}{7}$