?$ $?解：生成氧氣的質(zhì)量：?$375.00\mathrm {g} - 365.40\mathrm {g}=9.6\mathrm {g}$?
?$ $?設(shè)過(guò)氧化氫的質(zhì)量為?$x，$?
?$ {2\mathrm {H}_{2}\mathrm {O}_{2}\xlongequal{\mathrm {MnO}_{2}}2\mathrm {H}_{2}\mathrm {O} + \mathrm {O}_{2}↑}$?
68 32
? $x$? 9.6g
?$ \frac {68}{32}=\frac {x}{9.6\mathrm {g}}，$?解得?$x=20.4\mathrm {g}$?
?$ $?答：?$75\mathrm {g}$?該過(guò)氧化氫溶液中過(guò)氧化氫的質(zhì)量為?$20.4\mathrm {g}。$?
