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電子課本網(wǎng) 第45頁

第45頁

信息發(fā)布者:
解:因為$6^2 = 36,$所以$\sqrt{36}=6。$
解:因為$0.9^2 = 0.81,$所以$-\sqrt{0.81}=-0.9。$
解:因為?$(\pm \frac {7}{3})^2=\frac {49}{9}$?
所以?$\pm \sqrt {\frac {49}{9}}=\pm \frac {7}{3}。$?
解:因為$(\pm4)^2 = 16,$所以$x=\pm4。$
解:?$x^2=\frac {121}{4}$?
因為?$(\pm \frac {11}{2})^2=\frac {121}{4}$?
所以?$x=\pm \frac {11}{2}。$?
解:?$x - 1 = \pm 3$?
當?$x - 1 = 3$?時,?$x = 4;$?當?$x - 1 = -3$?時,?$x = -2$?
所以?$x = 4$?或?$x = -2$?
解:由題意可得?$a+1≥0,$??$2a≥0$?
∴?$a≥0$?
?$ $?當?$a + 1 = 2a,$?即?$a = 1$?時,?$\sqrt {a + 1}=\sqrt {2a}$?
?$ $?當?$a + 1>2a,$?即?$0≤a<1$?時,?$\sqrt {a + 1}>\sqrt {2a}$?
?$ $?當?$a + 1<2a,$?即?$a>1$?時,?$\sqrt {a + 1}<\sqrt {2a}$?