解:??$2y^2+5y + 1 = 0$??
??$y^2+\frac {5}{2}y=-\frac {1}{2}$??
??$y^2+\frac {5}{2}y+\frac {25}{16}=-\frac {1}{2}+\frac {25}{16}$??
??$(y+\frac {5}{4})^2=\frac {17}{16}$??
??$y+\frac {5}{4}=±\frac {\sqrt {17}}{4}$??
??$y_{1}=\frac {-5 + \sqrt {17}}{4},$????$y_{2}=\frac {-5 - \sqrt {17}}{4}$??