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第9頁

信息發(fā)布者:
$\frac{2}{63}$
$\frac{1}{63}$
$13$
$\frac{2}{143}$
$\frac{1}{11}$
$\frac{1}{13}$
$\frac{1}{143}$

$\begin{aligned}&\frac{1}{3×5} + \frac{1}{5×7} + \frac{1}{7×9} + \cdots + \frac{1}{97×99}\\=&\frac{1}{2}×(\frac{1}{3} - \frac{1}{5} + \frac{1}{5} - \frac{1}{7} + \frac{1}{7} - \frac{1}{9} + \cdots + \frac{1}{97} - \frac{1}{99})\\=&\frac{1}{2}×\frac{32}{99}\\=&\frac{16}{99}\end{aligned}$
因為$\frac{6}{7}<1<\frac{12}{11}<\frac{13}{11},$根據(jù)積相等時,一個乘數(shù)越大,另一個乘數(shù)越小,所以$D > B > A > C。$