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第16頁(yè)

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$(\frac{5}{12} + \frac{1}{9} - \frac{3}{8})\times72$

 $=\frac{5}{12}\times72 + \frac{1}{9}\times72 - \frac{3}{8}\times72$

 $=30 + 8 - 27$

 $=11$

$\frac{8}{13}\div7 + \frac{1}{7}\times\frac{6}{13}$

 $=\frac{8}{13}\times\frac{1}{7} + \frac{1}{7}\times\frac{6}{13}$

 $=(\frac{8}{13} + \frac{6}{13})\times\frac{1}{7}$

 $=\frac{14}{13}\times\frac{1}{7}$

 $=\frac{2}{13}$

$2 - \frac{6}{13}\div\frac{9}{26} - \frac{2}{3}$

 $=2 - \frac{6}{13}\times\frac{26}{9} - \frac{2}{3}$

 $=2 - \frac{4}{3} - \frac{2}{3}$

 $=2 - (\frac{4}{3} + \frac{2}{3})$

 $=2 - 2$

 $=0$

$5 - (\frac{6}{7}\div\frac{3}{14} + \frac{3}{16})$

 $=5 - (\frac{6}{7}\times\frac{14}{3} + \frac{3}{16})$

 $=5 - (4 + \frac{3}{16})$

 $=5 - 4 - \frac{3}{16}$

 $=1 - \frac{3}{16}$

 $=\frac{13}{16}$

 解：$1 + 25\%x = 10$

 $25\%x = 10 - 1$

 $25\%x = 9$

 $x = 9\div25\%$

 $x = 36$

 解：$\frac{3}{4}x + \frac{1}{6}x = \frac{11}{20}$

 $\frac{9}{12}x + \frac{2}{12}x = \frac{11}{20}$

 $\frac{11}{12}x = \frac{11}{20}$

 $x = \frac{11}{20}\div\frac{11}{12}$

 $x = \frac{11}{20}\times\frac{12}{11}$

 $x = \frac{3}{5}$

 解：$\frac{3}{4}x\div\frac{6}{5} = \frac{3}{5}$

 $\frac{3}{4}x = \frac{3}{5}\times\frac{6}{5}$

 $\frac{3}{4}x = \frac{18}{25}$

 $x = \frac{18}{25}\div\frac{3}{4}$

 $x = \frac{18}{25}\times\frac{4}{3}$

 $x = \frac{24}{25}$

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