$(\frac{24}{19}+\frac{16}{17})\times\frac{1}{8}+\frac{15}{17}$
$=\frac{24}{19}\times\frac{1}{8}+\frac{16}{17}\times\frac{1}{8}+\frac{15}{17}$
$=\frac{3}{19}+\frac{2}{17}+\frac{15}{17}$
$=\frac{3}{19}+(\frac{2}{17}+\frac{15}{17})$
$=\frac{3}{19}+1$
$=1\frac{3}{19}$(或$\frac{22}{19}$)