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電子課本網(wǎng) 第34頁(yè)

第34頁(yè)

信息發(fā)布者:
1.6
解:設(shè)該固體樣品中$CaO_{2}$的質(zhì)量為$x。$
$2CaO_{2}+2H_{2}O = 2Ca(OH)_{2}+O_{2}\uparrow$
$144$ $32$
$x$ $1.6g$
$\frac{144}{32}=\frac{x}{1.6g}$ ,$x = 7.2g$
該固體樣品中$CaO_{2}$的質(zhì)量分?jǐn)?shù)為$\frac{7.2g}{20g}\times100\% = 36\%$
答:該固體樣品中$CaO_{2}$的質(zhì)量分?jǐn)?shù)為$36\%。$
30
2.64
解:設(shè)該樣品中碳酸鈣的質(zhì)量為$x。$
$CaCO_{3}+2HCl = CaCl_{2}+H_{2}O+CO_{2}\uparrow$
$100$ $44$
$x$ $2.64g$
$\frac{100}{44}=\frac{x}{2.64g}$, $x = 6g$
該樣品中碳酸鈣的質(zhì)量分?jǐn)?shù)為$\frac{6g}{10g}\times100\% = 60\%$
答:該樣品中碳酸鈣的質(zhì)量分?jǐn)?shù)為$60\%。$