解:設(shè)該固體樣品中$CaO_{2}$的質(zhì)量為$x。$
$2CaO_{2}+2H_{2}O = 2Ca(OH)_{2}+O_{2}\uparrow$
$144$ $32$
$x$ $1.6g$
$\frac{144}{32}=\frac{x}{1.6g}$ ,$x = 7.2g$
該固體樣品中$CaO_{2}$的質(zhì)量分?jǐn)?shù)為$\frac{7.2g}{20g}\times100\% = 36\%$
答:該固體樣品中$CaO_{2}$的質(zhì)量分?jǐn)?shù)為$36\%。$