解:因?yàn)?$\vert a + 2\vert +(b - 1)^2=0,$?
所以?$a + 2 = 0,$??$b - 1 = 0,$?
解得?$a=-2,$??$b = 1。$?
?$ $?原式?$=a^2-2ab + 2(a^2-b^2)+a^2+2ab + b^2$?
? $ =a^2-2ab + 2a^2-2b^2+a^2+2ab + b^2$?
? $ =4a^2-b^2$?
?$ $?把?$a=-2,$??$b = 1$?代入得:
原式?$=4×(-2)^2-1^2=16 - 1 = 15$?