?$解：將△DEF豎直向上平移，使點(diǎn)D與點(diǎn)B重合，點(diǎn)E與點(diǎn)A重合，得到△BAG，$?
?$△BCD水平向左平移，使得點(diǎn)D與點(diǎn)F重合，點(diǎn)C與點(diǎn)A重合，得到△GAF，$?
?$如下圖，$?
?$則△DEF≌△BAG，△BCD≌△GAF，GB∥FD，GF∥BD， $?
?$∴S_{△EDF}=S_{△BAG}，S_{△BCD}=S_{△GAF}. $?
?$∵FD⊥BD， $?
?$∴S六邊形ABCDEF=S_{△DEF}+S_{△BCD}+S_{四邊形BDFA} $?
?$=S_{△BAG}+S_{△GAF}+S_{四邊形BDFA} $?
?$=FD?BD $?
?$=24×18 $?
?$=432.$?
?$即六邊形ABCDEF的面積是432$
