解：設(shè)需要稀鹽酸的質(zhì)量為?$x。$?
?$\mathrm {Zn}+2\mathrm {HCl}\xlongequal[ ]{ }\mathrm {ZnCl}_2+\mathrm {H}_2↑$?
73 2
3.65%×?$x$? 0.2g
?$\frac {73 }{2 }=\frac {3.65\%×x }{0.2\mathrm {g} }，$?解得?$x= 200\mathrm {g}$?
則需要該稀鹽酸的體積為?$\frac {200\mathrm {g} }{1.02\mathrm {m}/\mathrm {mL} }≈196.1\mathrm {mL}$?
答：需要?$3.65\%$?的稀鹽酸的體積為?$196.1\mathrm {mL}。$?
