解：設(shè)需要調(diào)配熟石灰的質(zhì)量為?$x。$?
?$\mathrm {Ca}(\mathrm {OH)}_2+\mathrm {H}_2\mathrm {SO}_4\xlongequal[ ]{ }\mathrm {CaSO}_4+2\mathrm {H}_2\mathrm {O}$?
74 98
? $x$? 98%×0.5t
?$\frac {74 }{98 }=\frac {x }{98\%×0.5\mathrm {t} }，$?解得?$x=0.37\mathrm {t} $?
答：需要調(diào)配熟石灰的質(zhì)量為?$0.37\mathrm {t}。$?
