解：醋酸鈣樣品中含醋酸鈣的質(zhì)量?$= 50.0 \mathrm {g}×94.8\%=47.4 \mathrm {g}$?
設(shè)生成氧化鈣的質(zhì)量為?$x。$?
?$(\mathrm {CH}_3\mathrm {COO)}_2\mathrm {Ca}\xlongequal[]{高溫}\mathrm {CaO}+\mathrm {C}_3\mathrm {H}_6\mathrm {O}↑+\mathrm {CO}_2↑$?
158 56
47.4 g ?$x$
?
?$\frac {158}{56}=\frac {47.4 \mathrm {g}}{ x}，$?解得?$x=16.8 \mathrm {g}$
?
答：生成氧化鈣的質(zhì)量為?$16.8 \mathrm {g}。$?
