電子課本網(wǎng) › 第86頁(yè)

第86頁(yè)

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$ 解：V_球=V_總-V_水=80\ \text {cm}^3-50\ \text {cm}^3=30\ \text {cm}^3$

$V_鐵=\frac {m_鐵}{ρ_鐵}=\frac {158\ \text {g}}{7.9\ \text {g/cm}^3}=20\ \text {cm}^3$

$V_鐵\lt V_球，所以是空心的$

$V_空=V_球-V_鐵=30\ \text {cm}^3-20\ \text {cm}^3=10\ \text {cm}^3$

$解：(1)ρ_液=\frac {?m }{?V}=\frac {(107-86) g}{(58-37) cm^3}=1\ \text {g/cm}^3$

$m_1=ρ_液V_{1}=1\ \text {g/cm}^3×37\ \text {cm}^3= 37\ \text {g}$

$m_容=m_{總1}-m_{1}=86\ \text {g}-37\ \text {g}=49\ \text {g}$

$(2)由(1)知ρ_液=1\ \text {g/cm}^3$

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