解：由?$①$?可得?$2x-y=2③$?
將?$③$?代入?$②$?得?$\frac {3(2x-y)+4}6+2y=12，$?即?$\frac {3×2+4}6+2y=12$?
∴?$\frac {5}{3}+2y=12，$?解得?$y=\frac {31}{6}$?
將?$y=\frac {31}{6}$?代入?$③$?得?$x=\frac {43}{12}$?
∴方程組的解為?$\begin {cases}{x=\frac {43}{12}}\\{y=\frac {31}{6}}\end {cases}$?
