電子課本網(wǎng) › 第105頁

第105頁

信息發(fā)布者：

$解：原式?=\frac {\sqrt{2y}}{3x\sqrt{2x}}?$

$?=\frac {\sqrt{xy}}{3x^2}?$

$解：原式=-\sqrt{(a-1)^2×(-\frac 1{a-1})}?$

$\ \ \ \ \ \ \ \ ?=-\sqrt{1-a}?$

$解:原式?=\frac {\sqrt{11}×\sqrt{3}}{\sqrt{3}×\sqrt{3}}?$

$?=\frac {\sqrt{33}}{3}$

$解:原式?=\frac {\sqrt{14}×\sqrt{6}}{\sqrt{6}×\sqrt{6}}?$

$?=\frac {\sqrt{21}}{3}?$

$解:原式?=\frac {3\sqrt{y}}{x\sqrt{y}×\sqrt{y}}?$

$?=\frac {3\sqrt{y}}{xy}?$

$解：?(1)\frac {1}{1+\sqrt{2}}=\frac {1-\sqrt{2}}{(1+\sqrt{2})(1-\sqrt{2})}=-(1-\sqrt{2})=-1+\sqrt{2}?$

$?(2)\frac 1{\sqrt{n}+\sqrt{n+1}}=-\sqrt{n}+\sqrt{n+1}?$

$?(3)?原式?=(-1+\sqrt{2}-\sqrt{2}+\sqrt{3}-\sqrt{3}+\sqrt{4}+...-\sqrt{2014}+\sqrt{2015})×(1+\sqrt{2015})?$

$? =(-1+\sqrt{2015})(1+\sqrt{2015})?$

$? =2015-1?$

$? =2014?$

亚洲激情+欧美激情,无码任你躁久久久久久,我的极品美女老婆,性欧美牲交在线视频,亚洲av高清在线一区二区三区