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電子課本網(wǎng) 第102頁(yè)

第102頁(yè)

信息發(fā)布者:
$解:原式??=\sqrt{\frac {40}{10}}??$
$??=2??$

$解:原式??=\sqrt{\frac 92÷\frac 94}??$
$??=\sqrt{2}$
$解:原式??=6÷(-3)×\sqrt{72÷6}??$
$??=-2\sqrt{12}??$
$??=-4\sqrt{3}?$
$解:原式??=\sqrt{\frac {56}7}??$
$??=2\sqrt{2}??$
$解:原式??=\frac {\sqrt{3}}{\sqrt{25}}??$
$??=\frac {\sqrt{3}}{5}??$
$解:原式??=\sqrt{\frac {5×25+3}{25}}??$
$??=\sqrt{\frac {64×2}{25}}??$
$??=\frac {8\sqrt{2}}{5}$
$解:原式??=\frac {\sqrt{81x^3}}{\sqrt{25y^2}}??$
$?? =\frac {9x\sqrt{x}}{5y}$
A
C
$解:原式??=\sqrt{27a^4÷3a^2}??$
$?? =\sqrt{9a^2}??$
$?? =3a??$
$解:原式??=4÷2×\sqrt{6x^3÷\frac x 3}??$
$?? =2\sqrt{18x^2}??$
$?? =6x\sqrt{2}??$
$解:原式??=\frac {\sqrt{(x-2y)^2}}{\sqrt{x^2}}??$
$?? =\frac {x-2y}x$
$解:原式??=\frac 1{2b-a}×\frac {\sqrt{(a-2b)^2}}{\sqrt{a^2b^2}}??$
$?? =\frac 1{2b-a}×\frac {a-2b}{ab}??$
$?? =-\frac 1{ab}??$