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電子課本網(wǎng) 第100頁

第100頁

信息發(fā)布者:

13
?$\frac {1}{12}$?
?$\frac {1}{8}$?
?$\frac {1}{4}$?
?$1-\frac {63}{64}$?
0
?$\frac {25}{33}$?
11
21
?$= (1-\frac {1}{2})+(1- \frac {1}{4} )+(1- \frac {1}{8} )+···+ (1-\frac {1}{256})$?
?$=8-( \frac {1}{2} +\frac {1}{4}+\frac {1}{8}+···+\frac {1}{256})$?
?$=8-(1-\frac {1}{256} )$?
?$=7 \frac {1}{256}$?
=0.5+1+1.5+2+···+4.5
=(0.5+4.5)×9÷2
=22.5
?$10$?分鐘?$=\frac {1}{6}$?小時
?$\frac {5}{7}-\frac {1}{6}+\frac {5}{7}=\frac {53}{42}($?小時?$)$?
答:這名游客上山、下山共用了?$\frac {53}{42}$?小時。
?$\frac {11}{12}-(\frac {1}{4}+\frac {1}{4}+\frac {1}{6})=\frac {1}{4}($?噸?$)$?
答:原來乙倉庫存糧?$\frac {1}{4}$?噸。
?$1?(\frac {1}{2}+\frac {1}{4}+\frac {1}{8}+\frac {1}{16})=1?(1?\frac {1}{16})=\frac {1}{16} $?
答:還??倲?shù)的?$\frac {1}{16}。$?



?$ \frac {1}{2} +\frac 13+ \frac {1}{6} =1$?
?$[19,$??$5]=95$?
?$\frac {x}{19}<\frac {4}{5}<\frac {y}{19}$?可以改寫為?$\frac {5x}{95}<\frac {76}{95}<\frac {5y}{95}$?
?$5x<76<5y$?
所以?$x=15,$??$y=16$?